In a hardy-weinberg population, 16% of individuals display the homozygous recessive phenotype. What proportion of the population will be heterozygous carriers of the recessive allele?.

Answer :

The proportion of the population will be heterozygous carriers of the recessive allele is 0.48.

What is Hardy-Weinberg principle?

  • Hardy-Weinberg principle says that the allele frequencies in a population are stable and is constant from generation to generation. The gene pool (total genes and their alleles in a population) remains a constant. This is called genetic equilibrium. Sum total of all the allelic frequencies is 1.
  • Individual frequencies, for example, can be named p, q, etc. In a diploid, p and q represent the frequency of allele A and allele a.
  • The frequency of AA individuals in a population is simply . This is simply stated in other ways, i.e., the probability that an allele A with a frequency of p appear on both the chromosomes of a diploid individual is simply the product of the probabilities, i.e.,.
  • Similarly. that of aa isand of Aa 2pq.
  • Hence, p²+2pq+q²=1, is a binomial expansion of (p+q)².

By given data;

[tex]q2=16[/tex]

[tex]q2=\frac{16}{100}=0.16[/tex]

[tex]q=0.4[/tex]

[tex]p=1-0.4=0.6[/tex]

[tex]2pq=2(0.6)(0.4)=0.48\\[/tex]

To learn more about Hardy-Weinberg principle:

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