Answer :
A) 110 - (3 × 14x) = 68
B) 3×14 is 42 so he spent $42 in two weeks 42+68= 110 so he had $110 to begin with
C) he will run out of money in about 22 days (22.6666666667)
B) 3×14 is 42 so he spent $42 in two weeks 42+68= 110 so he had $110 to begin with
C) he will run out of money in about 22 days (22.6666666667)
Spent a day = $3
After 14 days = $68 left
a) x = 3
14x = - 68
14x + 68 = 0
b) 14(3) + 68 = $120
c) total money = y
y - 14x = 120
y = 14(3) + 120
y = 172
172 - 3n = 0
3n = 172
n = 57 days and 8 hours
Sorry If I am wrong,but I've tried my best to give you the solution..
After 14 days = $68 left
a) x = 3
14x = - 68
14x + 68 = 0
b) 14(3) + 68 = $120
c) total money = y
y - 14x = 120
y = 14(3) + 120
y = 172
172 - 3n = 0
3n = 172
n = 57 days and 8 hours
Sorry If I am wrong,but I've tried my best to give you the solution..