Answer :
we know that
if sin A=cos B
then
angle A and angle B are complementary angles
A+B=90°
in this problem
sin49°=cosx
so
49°+x=90-------> x=90-49--------> x=41°
the answer is
x=41°
if sin A=cos B
then
angle A and angle B are complementary angles
A+B=90°
in this problem
sin49°=cosx
so
49°+x=90-------> x=90-49--------> x=41°
the answer is
x=41°
Answer:
[tex]x=41^o[/tex]
Step-by-step explanation:
We have been given an equation [tex]sin(49^o)=cos(x)[/tex] and we are asked to find the value of x.
Since we know that trigonometric ratios are applied to right triangles and we also know that [tex]sin(a)=cos(b)[/tex], where a and b are the angles other than 90 degree angle.
As one angle of our triangle is given 49 degrees, so to find the value of angle x we need to subtract 49 degrees from 90 degree angle as 49 degree angle and x will be equal to 90 degrees.
[tex]x=90^o-49^o[/tex]
[tex]x=41^o[/tex]
Therefore, the value of x is 41 degrees.