Answer :

missbianca
The value of B = 2x (3x^2 + 1) (2x + 5)

Given: 12x^4 + 30x^3 + 4x^2 + 10x

Req'd: B = ?

Sol'n:

*use elimination

solving for B:

= 2x (6x^3 +15x^2 + 2x +5)
= 2x (3x^2(2x + 5 +2x +5)
= 2x (3x^2 + 1) (2x + 5)

Answer:

[tex]B=3[/tex]

Step-by-step explanation:

We have been given an expression [tex]12x^4+30x^3+4x^2+10x[/tex].

Let us factor our given expression to answer the given problem.

Factor out [tex]2x[/tex] from all terms:

[tex]2x(6x^3+15x^2+2x+5)[/tex]

Now, we will make two groups of [tex]6x^3+15x^2+2x+5[/tex] as shown below:

[tex]2x((6x^3+15x^2)+(2x+5))[/tex]

[tex]2x((6x^3+15x^2)+(2x+5))[/tex]

Factor out [tex]3x^2[/tex] from 1st group:

[tex]2x((3x^2(2x+5))+(2x+5))[/tex]

[tex]2x(3x^2+1)(2x+5)[/tex]

Upon comparing [tex]2x(3x^2+1)(2x+5)[/tex] with [tex]Ax(Bx^2+1)(2x+5)[/tex], we can see that [tex]A=2[/tex] and [tex]B=3[/tex].

Therefore, the value of B is 3.

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