Answer :
[tex] |\Omega|=17\\
|A|=\underbrace{7}_{\text{red}}+\underbrace{9}_{\text{odd}}-\underbrace{4}_{\text{duplicate of red and odd}}=12\\\\
P(A)=\dfrac{12}{17}\approx71\% [/tex]
[tex] |\Omega|=17\\
|A|=\underbrace{7}_{\text{red}}+\underbrace{9}_{\text{odd}}-\underbrace{4}_{\text{duplicate of red and odd}}=12\\\\
P(A)=\dfrac{12}{17}\approx71\% [/tex]