haxassyn
Answered

Which of the following statements are true about the equation below?

x^2-6x+2=0

( 1 ) The graph of the quadratic equation has a minimum value.
( 2 ) The extreme value is at the point (3,-7).
( 3 ) The extreme value is at the point (7,-3).
( 4 ) The solutions are x = -3 + or - the square root of 7 .
( 5 ) The solutions arex = 3 + or - the square root of 7.
( 6 ) The graph of the quadratic equation has a maximum value.

Answer :

Blacklash

Answer:

Option 1, 2, 5 are the correct answer.

Explanation:

 We have the quadratic equation, [tex]x^2-6x+2=0[/tex]

 First derivative of the equation is given by 2x - 6 = 0

               So x = 3

At x = 3 the value of quadratic equation is extreme, corresponding y is given by [tex]3^2-6*3+2=11-18=-7[/tex], So extreme value is at (3,-7)

Second derivative of the quadratic equation is given by 2 ( positive value)

 Second derivative is positive so graph of equation has a minimum value.

Now root of the equation [tex]x^2-6x+2=0[/tex] is given by

            [tex]\frac{6+\sqrt{(-6)^2-4*1*2}} {2} =3+\sqrt{7}[/tex]

                                             or

            [tex]\frac{6-\sqrt{(-6)^2-4*1*2}} {2} =3-\sqrt{7}[/tex]

Option 1, 2, 5 are the correct answer.              

             

laurentspencer319

The answer are

The graph of the quadratic equation has a minimum value.

The extreme value is at the point (3,-7).

The solutions are x = 3 ± [tex]\sqrt{7}[/tex].

Here is how it looks on Plato or any multiple select.

Hope this helps

${teks-lihat-gambar} laurentspencer319

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