Answer :

calculista
we know that
[surface area of the triangular pyramid]=area of the base+3*[area of lateral triangles]
area of the base=12*8/2-----> 48 cm²

area of one lateral triangle=12*10/2-----> 60 cm²
[surface area of the triangular pyramid]=48+3*[60]-----> 228 cm²

the answer is the option 
B) 228 cm2

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