Answer :
Missing question:
A. [PdZn(H2O)2(CO)2]Br4.
B. [Zn(H2O)2(CO)2]2[PdBr4].
C. [Pd(H2O)2][Zn(CO)2]Br4.
D. [Pd(H2O)2]2[Zn(CO)2]3Br4.
E. [Zn(H2O)2(CO)2][PdBr4].
Answer is: E. [Zn(H2O)2(CO)2][PdBr4]..
In this complex diaqua means two waters (H₂O), dicarbonyl means two carbonyl groups (CO), zinc(Zn) and palladium (Pd) are central atoms or metals, bromine has negative charge -1. Bromine, water and carbonyl are ligands.
A. [PdZn(H2O)2(CO)2]Br4.
B. [Zn(H2O)2(CO)2]2[PdBr4].
C. [Pd(H2O)2][Zn(CO)2]Br4.
D. [Pd(H2O)2]2[Zn(CO)2]3Br4.
E. [Zn(H2O)2(CO)2][PdBr4].
Answer is: E. [Zn(H2O)2(CO)2][PdBr4]..
In this complex diaqua means two waters (H₂O), dicarbonyl means two carbonyl groups (CO), zinc(Zn) and palladium (Pd) are central atoms or metals, bromine has negative charge -1. Bromine, water and carbonyl are ligands.
Answer:
[tex][Zn(H_2O)_2(CO)_2][PdBr_4][/tex]
Explanation:
Hello,
In this case, one could build-up the formula, via analyzing the name as follows:
- It says tetrabromopalladate (IV), it means that it is a mixed anion, composed by four bromine atoms (tetrabromo) and one palladium atom due suffix ate), therefore the anion is [tex][PdBr_4][/tex].
- By means of the cation, it starts by diaqua, so it has two [tex]H_2O[/tex] as an aquocation. Next, is says dicarbonyl, so two carbonyl groups [tex]C=O[/tex] are bonded as well. Finally, the metallic part is given by the presence of zinc, so the cation turns out as [tex][Zn(H_2O)_2(CO)_2][/tex] by complexity.
Therefore, the resulting formula is: [tex][Zn(H_2O)_2(CO)_2][PdBr_4][/tex]
Best regards.