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A turbine blade rotates with angular velocity ω(t) = 8.00 rad/s - 0.20 rad/s3 t 2. what is the angular acceleration of the blade at t = 6.8 s?

Answer :

keu
Given: ω(t) = 8.00 - 0.2*t^2

Differentiating both sides with respect to time we get:
angular acceleration = α(t) = -0.2 * 2 *t 

At t = 6.8 sec,
angular acceleration = α(t) = -0.2 * 2 *6.8 = -2.72 rad/s^2

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