There are 9 yellow and 4 purple balls in a bag. If you randomly choose balls one at a time, with replacement, what is the probability of choosing 1 yellow ball and then 2 purple balls?

Question 5 options:

165/5210


24/1329


144/2197


28/1335

Answer :

did you get a answer?

The correct answer is:


144/2197


Explanation:


Drawing the balls with replacement means that the events are independent. This means to find the probability of all 3 balls being drawn, we multiply.


The probability of drawing a yellow ball is 9/13, since there are 9 yellow balls out of 13 total.

The probability of drawing the first purple ball is 4/13, since there are 4 purple balls out of 13 total.

The probability of drawing the second purple ball is 4/13, since there are still 4 purple balls out of 13 total.


This gives us:

(9/13)(4/13)(4/13) = (9*4*4)/(13*13*13) = 144/2197.

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