Answer:
Step-by-step explanation:
we can use the substitution method to solve this system of equations .
Substitute y= 2x in second equation y= x^2-3
we get
[tex]2x=x^2-3\\x^2-2x-3=0[/tex]
Now factor the equation
[tex](x-3)(x+1)=0\\x-3=0 \\x+1=0[/tex]
We get
x=3 and x=-1
for x=3 y=2(3)=6
and for x=-1
y=2(-1)=-2
solution is
(3,6) and (-1,-2)
