Answer :
Solve for x:
3 x^2 - 7 x + 6 = 0
Divide both sides by 3:
x^2 - (7 x)/3 + 2 = 0
Subtract 2 from both sides:
x^2 - (7 x)/3 = -2
Add 49/36 to both sides:
x^2 - (7 x)/3 + 49/36 = -23/36
Write the left hand side as a square:
(x - 7/6)^2 = -23/36
Take the square root of both sides:
x - 7/6 = (i sqrt(23))/6 or x - 7/6 = -(i sqrt(23))/6
Add 7/6 to both sides:
x = 7/6 + (i sqrt(23))/6 or x - 7/6 = -(i sqrt(23))/6
Add 7/6 to both sides:
Answer: x = 7/6 + (i sqrt(23))/6 or x = 7/6 - (i sqrt(23))/6
3 x^2 - 7 x + 6 = 0
Divide both sides by 3:
x^2 - (7 x)/3 + 2 = 0
Subtract 2 from both sides:
x^2 - (7 x)/3 = -2
Add 49/36 to both sides:
x^2 - (7 x)/3 + 49/36 = -23/36
Write the left hand side as a square:
(x - 7/6)^2 = -23/36
Take the square root of both sides:
x - 7/6 = (i sqrt(23))/6 or x - 7/6 = -(i sqrt(23))/6
Add 7/6 to both sides:
x = 7/6 + (i sqrt(23))/6 or x - 7/6 = -(i sqrt(23))/6
Add 7/6 to both sides:
Answer: x = 7/6 + (i sqrt(23))/6 or x = 7/6 - (i sqrt(23))/6
Answer:
Discriminant of the quadratic is-23
Step-by-step explanation:
The given quadratic function is [tex]3x^2-7x+6[/tex]
Comparing with the expression [tex]ax^2+bx+c[/tex]
a = 3, b = -7, c = 6
The discriminant of the quadratic is given by [tex]D=b^2-4ac[/tex]
Substituting the known values, discriminant of the quadratic is
[tex]D=(-7)^2-4(3)(6)\\\\D=49-72\\\\D=-23[/tex]
Therefore, discriminant of the quadratic is-23