Answer :
Answer:
[tex]6\frac{2}{3}[/tex] of 18%, [tex]3\frac{1}{3}[/tex] water
Step-by-step explanation:
The 18% solution added to the water is equal to the 10 liters of 12% solution.
Let's say that the amount of 18% solution is x
18% of x = 0.18x
Let's say that the amount of water is 10-x
Because there is no alcohol in water, it will be 0(10-x), or just 0
0.18x + 0 = 10•0.12
0.18x = 1.2
x = [tex]6\frac{2}{3}[/tex]
10 - [tex]6\frac{2}{3}[/tex] = [tex]3\frac{1}{3}[/tex]
The volume required to dilute the concentration to 12% is 6.6L
Data;
- c1 = 18%
- v1 = ?
- c2 = 12%
- v2 = 10L
Dilution Formula
To solve this problem, we have to use dilution formula which is given as
[tex]c_1v_1 = c_2v_2[/tex]
we can convert the percentages to decimal and solve
[tex]c_1 = 18\% = 0.18\\c_2 = 12\% = 0.12[/tex]
Let's substitute the values and solve
[tex]c_1v_1 = c_2v_2\\0.18v_1 = 0.12*10\\0.18v_1 = 1.2\\v_1 = \frac{1.2}{0.18} \\v_1= 6.6L[/tex]
The volume required to dilute the concentration to 12% is 6.6L
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