we have
[tex]\frac{125^{2}}{125^{(4/3)}}[/tex]
The numerator and denominator has the same base, so subtract the exponents
[tex]\frac{125^{2}}{125^{(4/3)}}=125^{2-(4/3)}[/tex]
[tex]=125^{(2/3)}[/tex]
remember that
[tex]125=5^{3}[/tex]
substitute
[tex]=(5^{3})^{(2/3)}=(5)^{(6/3)}=5^{2}=25[/tex]
therefore
the answer is
[tex]25[/tex]
