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A certain gas is present in a 15.0 l cylinder at 2.0 atm pressure. if the pressure is increased to 4.0 atm the volume of the gas decreases to 7.5 l . find the two constants ki, the initial value of k, and kf, the final value of k, to verify whether the gas obeys boyle's law by entering the numerical values for ki and kf in the space provided.

Answer :

shinmin

In the first condition: P1 = 2.0 atm V1 = 15.0 L P1V1 = Ki 2 * 15 = Ki Ki = 30

In the second condition Pt = 4.0 atm Vt = 7.5L Pt * Vt = Kt 4.0 * 7.5 = Kt Kt = 30

Conclusion: Ki = Kt. Since the two values of k are the same. Therefore, the gas obeys Boyle's Law. Take note Boyle’s law is an ideal gas law which tells us that the volume of an ideal gas is contrariwise proportional to its absolute or total pressure at a constant temperature.

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