Answer :
[tex]\bf \textit{equation of a circle}\\\\
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad
\begin{array}{lllll}
center\ (&{{ h}},&{{ k}})\qquad
radius=&{{ r}}\\
&0&0&7
\end{array} [/tex]
Answer:
[tex]x^2 + y^2 = 49[/tex]
Step-by-step explanation:
Since, the equation of a circle is,
[tex](x-h)^2 + (y-k)^2 = r^2[/tex]
Where,
(h, k) is the center of the circle,
r = radius of the circle,
Here, (h, k) = (0, 0) ( origin ),
r = 7 units,
Hence, the equation of the circle is,
[tex](x-0)^2 + (y-0)^2 = 7^2[/tex]
[tex]\implies x^2 + y^2 = 49[/tex]