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for the cross aabbccdd x aabbccdd, what is the probability that any one offspring will have the phenotype abcd? assume independent assortment and complete dominance. enter the exact answer (not rounded)

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For the cross aabbccdd x aabbccdd, the probability that any one offspring will have the phenotype abcd is .09375.

According to Mendel's law of independent assortment, genes have no impact on the sorting of alleles into gametes: any potential combination of alleles for every gene is equally likely to occur.

The dihybrid cross exemplifies the independent assortment of genes: a cross between two true-breeding parents who display separate phenotypes for two attributes. Consider the seed color and texture features of two pea plants: one with green, wrinkled seeds (yyrr) and another with yellow, spherical seeds (YYRR).

Because each parent is homozygous, the rule of segregation predicts that the green/wrinkled plant's gametes are all yr, but the yellow/round plant's gametes are all YR.

Learn more about  independent assortment at https://brainly.com/question/2376592

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