Answered

Question 1. An insurance company selected samples of clients under 18 years of age and over 18 and recorded the number of accidents they had in the previous year. The results are shown below. Over Age of 18: n1 = 500 Number of accidents = 180 Under Age of 18: n2 = 600 Number of accidents = 150 We are interested in determining if the accident proportions differ between the two age groups. Let pu represent the proportion under and po the proportion over the age of 18. The null hypothesis is Pu-Po = 0 Pu-P. £0 Pu-P.10 Pu - P. 30 Question 2. Refer to Question 1. What is the value of the pooled proportion? Round your answer to three decimal places.
Question 3. Refer to Questions 1 and 2. Determine the value of the standard error of the difference in the proportions. Round your answer to four decimal places.

Answer :

The pooled proportion is 0.200 and the standard error of the difference in the proportions is 0.0201.

1. The null hypothesis is Pu-Po = 0, which means that the proportion of people under 18 who had accidents is the same as the proportion of people over 18 who had accidents.

2. To calculate the pooled proportion, we first add the total number of people in each group (500 + 600 = 1100). Then we add the total number of accidents in each group (180 + 150 = 330). Finally, we divide the total number of accidents by the total number of people to get the pooled proportion (330/1100 = 0.200).

3. The standard error of the difference in the proportions can be calculated using the formula SE = SQRT(P1*(1-P1)/n1 + P2*(1-P2)/n2), where P1 is the proportion of people under 18 who had accidents, P2 is the proportion of people over 18 who had accidents, and n1 and n2 are the number of people in each group. In this case, P1 = 150/600 = 0.250, P2 = 180/500 = 0.360, n1 = 600, and n2 = 500. Plugging these values into the formula gives us SE = SQRT(0.250*(1-0.250)/600 + 0.360*(1-0.360)/500) = 0.0201.

Learn more about error here

https://brainly.com/question/13370015

#SPJ4

Other Questions