Answer :
When the following code section runs, the value of the variable y will be -2.
Given that,
We have to find when the following code section runs, what value will the variable y have? Assume the following input values:
The code mentioned above is explained in the section below.
Here, x=5, n=0, and the input values are 1–6.
So, x>3 is true.
Control will go to second if block and input y and z.
Now y=1 and z=2 and n=1
Next control goes to if(x) since x>0 which is true.
Now z=3 and x=4 and y=0 and n=0
Her n==0 so r=z- ++x => 3- (5) =>-2.
Hence r=-2
Therefore, the variable r=-2 is the output for the code.
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