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Chemistry

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how many moles of ba(oh)2ba(oh)2 are present in 185 mlml of 0.200 mm ba(oh)2ba(oh)2 ? express your answer with the appropriate units.

Answer :

jaiswaljyoti jaiswaljyoti

Today at 9:35 AM

There are 0.18 moles of ba(oh)2 in the given reactions.

Volume = 185 ml = 185L

Molarity M = 0.200 m

Molarity M is number of moles/Volume in liter

So,

n = M×V

n = 0.200 × 0.185 = 0.18 mol

The molarity of a given solution has defined as the total number of moles of solute per litre of solution. The volume of a solution depends on changes in the physical conditions of the system, such as pressure and temperature, as opposed to mass, which fluctuates with changes in the system's physical circumstances. Molarity is denoted by the letter M, also known as a molar.

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