Answer :
The temperature is a chilly 3.1 k, and there are only 106 atoms per cubic meter of air in the deep vacuum between galaxies. 3.86*10⁻¹⁷ pa is the pressure.
Density of atoms,[tex]\rho= 10^6 atoms/m^3[/tex]
Temperature, T= 2.8K
using Ideal Gas Equation,
PV= nRT
where n= number of moles,
R= Universal Gas Constant
P= Pressure
Number of atoms in 1 mole, [tex]N_A= 6.022 \times 10^{23}[/tex]
Then given number of atoms will have following number of moles, [tex]n= \frac{10^6}{N_A}[/tex]
where NA= Avogadro's number which is constant
Or we can write,
[tex]\frac{n}{V}= \frac{\rho}{N_A}[/tex]
Thus Pressure will be
[tex]P= \frac{nRT}{V}= \frac{\rho RT}{N_A}[/tex]
using given and known values in above,
[tex]P= \frac{10^6 \times 8.314 \times 2.8}{6.022 \times 10^{23}}= 3.86 \times10^{-17} Pa[/tex]
Learn more about pressure here:
https://brainly.com/question/28012687
#SPJ4