Mauds06
Answered

How many grams of oxygen are formed when 6.21 moles of KOH are formed?
4 KO(s) + 2 H2O(l) → 4 KOH(s) + O2(g)

Answer :

taskmasters
From the given balanced chemical equation, it can be seen that for every 4 moles of KOH formed, only 1 mole of O2 is formed. From this ratio extracted from the equation, 
                   moles O2 = (6.21 moles) x (1 mole O2/4 moles KOH) 
                   moles O2 = 1.5525 moles O2
Then, we determine the mass in grams by multiplying the calculated value with the molar mass of oxygen, equal to 32. 
 The answer is therefore equal to 49.68 grams. 
tutorAnne

49.6 grams of oxygen are formed.

Finding Grams /Mass using Stoichiometry

The balanced chemical reaction is:

4 KO(s) + 2 H2O(l) → 4 KOH(s) + O2(g)

First we calculate the moles of Oxygen

We can see from the balanced chemical reaction that,

  • When 4 moles of KOH formed then 1 mole of O2 will be formed

So,

  • when 6.21 moles of KOH formed (6.21 /4) 1.55  moles of Oxygen will be formed

To calculate the mass of O2, We use

Number of moles x molar mass =Mass

Molar mass of  Oxygen= 32 g/mol

Therefore, the mass of oxygen formed will be 1.55  moles x 32g/mol

are 49.6 grams.

Learn more on finding gramsof elemednts from stoichiometry:https://brainly.com/question/6669486

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