Answer :

1) List the known quantities

Initial conditions

Concentration 1: 1.6 M

Volume 1: 175 mL

Final conditions

Volume 2: 1 L

Concentration 2: unknown

2) Set the equation

[tex]C1*V1=C2*V2[/tex]

3) Convert units

Volume

1 L = 1000 mL

[tex]mL=1\text{ }L*\frac{1000\text{ }mL}{1\text{ }L}=1000\text{ }mL[/tex]

4) Plug in the known quantities and solve for C2

[tex](1.6\text{ }M)*(175\text{ }mL)=C2*(1000\text{ }mL)[/tex]

[tex]C2=\frac{(1.6\text{ }M)*(175\text{ }mL)}{(1000\text{ }mL)}[/tex][tex]C2=0.28\text{ }M[/tex]

The new concentration is 0.28 M.

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