Answer :

According to the problem, the recursive rule is

[tex]\begin{gathered} f(1)=15 \\ f(n)=f(n-1)-6 \end{gathered}[/tex]

This means the first term of the sequence is 15.

So, for n = 2, we have

[tex]f(2)=f(2-1)-6=f(1)-6[/tex]

But, we know that f(1) = 15, so

[tex]f(2)=15-6=9[/tex]

The second term is 9.

For n = 3.

[tex]f(3)=f(3-1)-6=f(2)-6[/tex]

But, we know that f(2)=9, so

[tex]f(3)=9-6=3[/tex]

Therefore, the third term is 3.

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