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A player threw a ball from point P to 3rd Base. How far did the player throw the ball? Round the answer to the nearest foot.A).210ftB).150ftC).127ftD).79ft

A player threw a ball from point P to 3rd Base. How far did the player throw the ball? Round the answer to the nearest foot.A).210ftB).150ftC).127ftD).79ft class=

Answer :

Answer:

B).150ft

Explanation:

The distance from homeplate to 1st Base = 90 feet

Therefore: distance from homeplate to point P is:

[tex]90+30=120ft[/tex]

The distance from homeplate to 3rd base is 90 feet.

We see that the problem forms a right-triangle where the distance from point P to 3rd Base is the Hypotenuse.

Using Pythagoras Theorem:

[tex]\begin{gathered} \text{Distance}^2=120^2+90^2 \\ Dis\tan ce=\sqrt[]{120^2+90^2} \\ =\sqrt[]{22500^{}} \\ =150ft \end{gathered}[/tex]

The player threw the ball a distance of 150 feet.

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