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f(x) = 3x³+4x² - 8x - 2
g(x) = 3x - 5
Find (f - g)(x).
A. (f-g)(x) = 3x³ + 4x² - 5x+3
B. (f-g)(x) = 3x³+4x² - 11x +3
C. (f-g)(x) = 3x³ + 4x² - 11x – 7
D. (ƒ − g)(x) = 3x³ + 4x² − 5x – 7

f(x) = 3x³+4x² - 8x - 2g(x) = 3x - 5Find (f - g)(x).A. (f-g)(x) = 3x³ + 4x² - 5x+3B. (f-g)(x) = 3x³+4x² - 11x +3C. (f-g)(x) = 3x³ + 4x² - 11x – 7D. (ƒ − g)(x) = class=

Answer :

Given the functions:

[tex]\begin{gathered} f(x)=3x^3+4x^2-8x-2 \\ g(x)=3x-5 \end{gathered}[/tex]

Now (f-g)(x) will be equal to:

[tex](f-g)(x)=f(x)-g(x)[/tex]

Replacing:

[tex]\begin{gathered} (f-g)(x)=(3x^3+4x^2-8x-2)-(3x-5) \\ (f-g)(x)=3x^3+4x^2-8x-2-3x+5 \\ \end{gathered}[/tex]

Simplifying:

[tex](f-g)(x)=3x^3+4x^2-11x+3[/tex]

The answer is: B).

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