Answer :

we have the equation

[tex]q(x)=4x-\frac{3+8x}{5}=\frac{5(4x)-(3+8x)}{5}=\frac{20x-3-8x}{5}=\frac{12}{5}x-\frac{3}{5}[/tex]

so

[tex]q(x)=\frac{12}{5}x-\frac{3}{5}[/tex]

The slope is

m=12/5

Find out the y-intercept (value of y when the value of x=0)

For x=0

[tex]\begin{gathered} q(x)=\frac{12}{5}(0)-\frac{3}{5} \\ \\ q(x)=-\frac{3}{5} \end{gathered}[/tex]

therefore

The y-intercept is (0,-3/5)

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