Answer :
We will call the first number "x".
Thus, since the numbers have to be consecutive, the second integer will be "x+1", and the third integer "x+2".
We need for the sum of the first "x" and the third "x+2" to be equal to 80, so we will have the equation:
[tex]x+x+2=80[/tex]And now we solve this equation to find x.
First, add the like terms on the left side:
[tex]2x+2=80[/tex]Subtract 2 to both sides:
[tex]\begin{gathered} 2x+2-2=80-2 \\ 2x=80-2 \\ 2x=78 \end{gathered}[/tex]Divide both sides by 2:
[tex]\begin{gathered} \frac{2x}{2}=\frac{78}{2} \\ x=\frac{78}{2} \\ x=39 \end{gathered}[/tex]We have the first integer: 39
Thus, the second number is: 39+1=40
And the third number: 39+2=41
Answer: 39, 40 and 41