The Law of sines states:
[tex]\frac{\sin (\angle P)}{p}=\frac{\sin (\angle R)}{r}[/tex]Substituting with data, and solving for angle P, we get:
[tex]\begin{gathered} \frac{\sin(\angle P)}{2}=\frac{\sin(142)}{6.7} \\ \frac{\sin(\angle P)}{2}=\frac{0.615}{6.7} \\ \sin (\angle P)=0.091\cdot2 \\ \angle P=\arcsin (0.182) \\ \angle P=10.6\text{ \degree} \end{gathered}[/tex]