Hi, I am having some problems with this geometry question. We just learned tan, sin, and cosine. Can you help me?

The given triangle is
Recall that the formula for tan is
[tex]\tan \theta=\frac{Opposite\text{ side}}{\text{adjacent side}}[/tex][tex]\text{Substitute Opposite side=14 , adjacent side=x and }\theta=27^o,\text{ we get}[/tex][tex]\tan 27^o=\frac{14}{x}[/tex][tex]\text{Use }tan27^o=0.509.[/tex][tex]0.509=\frac{14}{x}[/tex][tex]x=\frac{14}{\text{0}.509}=27.505[/tex]Hence the x value is 27.5.