Answer :
Formula of speed, distance and time is:
[tex]\text{speed}=\frac{dis\tan ce\text{ }}{time}[/tex]Let distance is:
[tex]x[/tex]Speed of first jogger is:
[tex]S[/tex]For first jogger :
[tex]\begin{gathered} \text{speed}=\frac{dis\tan ce}{time} \\ S=\frac{x}{4.5} \end{gathered}[/tex]For the second jogger distance is same (x) and time is 3.5 minutes and speed is 1.5 then distance is:
[tex]\begin{gathered} \text{time}=3.5\times60 \\ =210\sec \text{.} \end{gathered}[/tex][tex]\begin{gathered} \text{speed}=\frac{dis\tan ce}{time} \\ 1.5=\frac{x}{210} \\ x=210\times1.5 \\ x=315\text{ ft} \end{gathered}[/tex]If distance is 315 ft then speed of first jogger is:
[tex]\begin{gathered} \text{time}=4.5\times60\text{ } \\ =270\text{ sec.} \end{gathered}[/tex][tex]\begin{gathered} \text{speed}=\frac{dis\tan ce}{time} \\ S=\frac{x}{270} \\ S=\frac{315}{270} \\ S=1.16\text{ ft./sec.} \end{gathered}[/tex]Second jogger is faster then first jogger then difference between speed is:
[tex]\text{Faster sp}eed\text{ =spe}ed\text{ of second jogger - sp}eed\text{ of first jogger}[/tex][tex]\begin{gathered} =1.5-1.16 \\ =0.34\text{ ft./sec.} \end{gathered}[/tex]The second jogger is faster 0.34 ft/sec. then the first jogger.