Answer :
Given:
[tex]\begin{gathered} \text{Principal(P)}=1000 \\ \text{rate of interest(r)=4 \%} \\ n=10\text{ years} \end{gathered}[/tex][tex]\begin{gathered} \text{Amount}=P(1+r)^n \\ =1000(1+0.04)^{10} \\ =1000((1.04)^{10} \\ =1000(1.48024) \\ =1480.24 \end{gathered}[/tex][tex]f(x)=1000(1.04)^x[/tex]