Answer :
Let's solve the equation:
[tex]\begin{gathered} 2e^{3t}=10 \\ e^{3t}=\frac{10}{2} \\ e^{3t}=5 \\ \ln (e^{3t})=\ln 5 \\ 3t=\ln 5 \\ t=\frac{1}{3}\ln 5 \\ t=0.536 \end{gathered}[/tex]
Let's solve the equation:
[tex]\begin{gathered} 2e^{3t}=10 \\ e^{3t}=\frac{10}{2} \\ e^{3t}=5 \\ \ln (e^{3t})=\ln 5 \\ 3t=\ln 5 \\ t=\frac{1}{3}\ln 5 \\ t=0.536 \end{gathered}[/tex]