Answer :
[tex]49\text{ }\frac{m}{s^2}[/tex]
Explanation
Newton's second law states that If a body has a net force acting on it, it is accelerated in accordance with the equation.
[tex]\begin{gathered} F=\text{ ma} \\ \text{where F is the force} \\ m\text{ is the mass} \\ a\text{ is the acceleration} \end{gathered}[/tex]then
Let
[tex]\begin{gathered} F=98\text{ N} \\ m=2.0\text{ Kg} \\ a=\text{unknown}=a \end{gathered}[/tex]now, replac3e in the expression and solve for a
[tex]\begin{gathered} F=ma \\ 98\text{ N=2.0 Kg}\cdot a \end{gathered}[/tex]to solve for a , divide both sides by 2.0 Kg
[tex]\begin{gathered} 98\text{ N=2.0 Kg}\cdot a \\ \frac{98\text{ N}}{\text{2.0 Kg}}\text{=}\frac{\text{2.0 Kg}\cdot a}{\text{2.0 Kg}} \\ 49\text{ }\frac{m}{s^2}=a \end{gathered}[/tex]therefore,the answer is
[tex]49\text{ }\frac{m}{s^2}[/tex]I hope this helps you