Answer :
We take the base and the measures
H is the hypotenuse, we can notices the line makes a right triangle then we can use pythagoras
[tex]a^2+b^2=h^2[/tex]where a and b are sides of the triangle and h the hypotenuse, then replacing
[tex](12)^2+(4)^2=H^2[/tex]simplify
[tex]\begin{gathered} 144+16=H^2 \\ 160=H^2 \end{gathered}[/tex]and use roots to solve H
[tex]\begin{gathered} \sqrt[]{160}=\sqrt[]{H^2} \\ \\ 4\sqrt[]{10}=H \\ \\ H=4\sqrt[]{10}\approx12.65 \end{gathered}[/tex]the hypotenuse of the base is 12.65 centimeters
