Answer :
Since the sample is normally distributed we need to use the z score formula:
[tex]Z=\frac{x-\mu}{\sigma}[/tex]where x is the value we want, mu is the mean and sigma is the deviation.
Now, we need the the probability:
[tex]\begin{gathered} P(10\leq X\leq16)=P(\frac{10-12}{8.2577}\leq Z\leq\frac{16-12}{8.2577}) \\ =P(-0.2421\leq Z\leq0.4843) \end{gathered}[/tex]