Answer :

Given:

[tex]\text{ lx-6l}\leq15[/tex]

Required:

We need to write solutions to inequalities in interval notation.

Explanation:

[tex]\text{lx-6l}\leqslant15[/tex]

now open mode

[tex]-15\leq\text{x-6}\leqslant15[/tex]

now add 6 every sides

[tex]\begin{gathered} -15+6\leqslant x-6+6\leqslant15+6 \\ -9\leq x\leq21 \end{gathered}[/tex]

Final answer:

Interval of solution is [-9,21]

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