Let us find each area of the flag using the next formula:
[tex]A=\frac{base\ast height}{2}[/tex]For the flag on the left:
[tex]\begin{gathered} A=\frac{18in\ast12in}{2} \\ A=\frac{216in^2}{2} \\ A=108in^2 \end{gathered}[/tex]For the flag on the right:
[tex]\begin{gathered} A=\frac{36in\ast18in}{2} \\ A=\frac{648in^2}{2} \\ A=324in^2 \end{gathered}[/tex]Then, 108 in²*3 = 324in²
Hence, the area of the flag on the right is greater 3 times than the area of the flag on the left.