Answer :
The HEAT released when 10.0 kg of KBr forms from its element is -3. 31 × 10^4 kJ
As we know that,
thermochemical equation for the decomposition of potassium bromide is
KBr ------- K + 1/2 Br2
Now, reversing the above equation the sign of heat also become opposite. Thus, reverse reaction can be written as
K + 1/2 Br2 ----KBr
∆H = - 394 kJ.
Given,
Molar mass of KBr = 119 g/mol
1 mol KBr = -394kJ
As we know that
1 kg = 10^3
Calculation of conversation factor
The desired conversation factor can be calculated as
10^3 × (1mol KBr/ 119 g KBr) × (-394KJ/ 1 mol KBr)
Calculation of heat released
heat released = given mass × conversion factor
= 10 kg KBr × 10^3 × (1mol KBr/ 119 g KBr) × (-394KJ/ 1 mol KBr)
= -3. 31 × 10^4 kJ
Thus, we calculated that the heat released when 10.0 kg of KBr forms from its element is -3. 31 × 10^4 kJ.
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