Answer :

The relative frequency for the class with lower class limit 15 is:

R = 10/41 = 0.244

How to find the relative frequency?

Let's suppose you have a set of N elements, such that K of these N elements has a given property.

Then the relative frequency for the elements with that given property is:

R = K/M

By looking at the table, we can see that the total number of students is:

T = 10 + 6 + 5 + 9 + 3 + 8 = 41

And 10 belong to the class with the lower class limit 15, then the relative frequency for that class is:

R = 10/41 = 0.244

If you want to learn more about relative frequency:

https://brainly.com/question/3857836

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