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A 25-cm rod moves at 5. 0 m/s in a plane perpendicular to a magnetic field of strength 0. 25 t. the rod, velocity vector, and magnetic field vector are mutually perpendicular, as?

Answer :

Magnetic field of the given solution is 2×[tex]10^{-19} N[/tex]

Similar to how an electric field surrounds an electric charge, the magnetic field is the area around a magnet which exert a magnetic force and it is a result of moving electric charges. Magnetic field lines are a visual tool used to represent magnetic fields.

By using the formula of motional emf i.e E = Blv

here, E = Induced emf

         B = magnetic field

         l = length of the conductor

         v = velocity

The magnetic field using the formula

      f = qv × B

The velocity of electrons and lod is same

by using above equations we get f = qvBsinθ

by putting the given values we get

  f = (1.6022×[tex]10^{-19}[/tex]) (5) (0.25t)

  f =  2×[tex]10^{-19} N[/tex]

Magnetic field of the given solution is 2×[tex]10^{-19} N[/tex]

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