How can the following expression be written so that no negative exponents appear?
(a5)³a-6
Q-2

Answer:
a^11
Step-by-step explanation:
1) Simplify the numerator. Use the laws: (x^a)^y = x^ay, x^a × x^b = x^a+b.
= a¹⁵ × a^-6 / a^-2
= a⁹ / a^-2
2) Divide them. Use the law: x^a / x^b = x^a - b.
= a^9 - (-2) / 1
= a^9 + 2 / 1
= a^11