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2. Employed Women If 60% of all women are employed
outside the home, find the probability that in a sample
of 20 women,
aid sel
Mil
2
a. Exactly 15 are employed
b. At least 10 are employed
c. At most 5 are not employed outside the home

Answer :

Using the binomial distribution, the probabilities are given as follows:

a) 0.0747 = 7.47%.

b) 0.8725 = 87.25%.

c) 0.1256 = 12.56%.

What is the binomial distribution formula?

The formula is:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

The values of the parameters are:

n = 20, p = 0.6.

Item a:

The probability is P(X = 15), hence:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 15) = C_{20,15}.(0.6)^{15}.(0.4)^{5} = 0.0747[/tex]

Item b:

The probability is:

[tex]P(X \geq 10) = P(X = 10) + P(X = 11) + P(X = 12) + \cdots + P(X = 20)[/tex]

Finding each value with the equation we used in item a, we have that:

[tex]P(X \geq 10) = 0.8725[/tex]

Item c:

At least 20 - 5 = 15 on the road, hence the probability is:

[tex]P(X \geq 15) = P(X = 15) + P(X = 16) + \cdots + P(X = 20)[/tex]

Then, using the same procedure as item b, we have that:

[tex]P(X \geq 15) = 0.1256[/tex]

More can be learned about the binomial distribution at https://brainly.com/question/24863377

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