Please help! If the current in a circuit is 3 + j2 amps and the resistance is 4 - j3 ohms, what is the voltage?

The value of the voltage is 18 - j volts if the current in a circuit is 3 + j2 amps and the resistance is 4 - j3 ohms option (c) is correct.
It is defined as the number which can be written as x+iy where x is the real number or real part of the complex number and y is the imaginary part of the complex number and i is the iota which is nothing but a square root of -1.
We have:
The current in a circuit is 3 + j2 amps and the resistance is 4 - j3 ohms.
As we know,
V = IR
V = (3 + j2)(4 - j3)
[tex]\rm V=\left(3\cdot \:4-2\left(-3\right)\right)+\left(3\left(-3\right)+2\cdot \:4\right)j[/tex]
j² = -1 (complex part)
After simplification:
V = 18 - j volts
Thus, the value of the voltage is 18 - j volts if the current in a circuit is 3 + j2 amps and the resistance is 4 - j3 ohms option (c) is correct.
Learn more about the complex number here:
brainly.com/question/10251853
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