Answer :

Murdrock

[tex]{\huge \underline{{ \fbox \color{red}{A}}{\fbox \color{green}{n}}{\fbox \color{purple}{s}}{\fbox \color{brown}{w}}{\fbox \color{yellow}{e}}{\fbox \color{gray}{r } }}}[/tex]

We have the data: radius, r = 3

We use the volume formula with the values we have:      

[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \mathsf{\blue{\blacktriangleright}} \sf \: V = \dfrac{4}{3} \times \pi \: \times r {}^{3} [/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \mathsf{\blue{\blacktriangleright}} \sf \: V= \dfrac{4}{3} \times \pi \times (3 {}^{3} )[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \mathsf{\blue{\blacktriangleright}} \sf \: V= \dfrac{4}{3} \times \pi \times 27[/tex]             

[tex]\: \: \: \: \: \: \: \: \: \: \: \: \: \mathsf{\blue{\blacktriangleright}} \sf \: V=113,1m {}^{3} [/tex]

Answer: The volume of the sphere is equal to 113,1 m.

So

Volume

  • 4)3πr³
  • 4/3π3³
  • 4/3π(27)
  • 36πm³

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