Answered

[tex]\sqrt[3]{x}=\sqrt[5]{32}[/tex]
why can't i just cube both sides, therefore kick the x out of the cubic root, and then i would have
[tex]x = \sqrt{32} \\then \\x = \sqrt{16 * 2}\\x = 4\sqrt{2}[/tex]

Answer :

gift1723

Answer:

[tex]x = 8[/tex]

Step-by-step explanation:

[tex] {x}^{ \frac{1}{3} } = {32}^{ \frac{1}{5} } [/tex]

[tex] {( {x}^{ \frac{1}{3} } )}^{3} = {( {32}^{ \frac{1}{5} } )}^{3} [/tex]

[tex] {x}^{1} = \sqrt[5]{ {32}^{3} } [/tex]

[tex]x = \sqrt[5]{32768} [/tex]

[tex]x = 8[/tex]

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