Answer:
7.8
Step-by-step explanation:
distance formula : [tex]d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
where the x and y values are derived from the given points
here the given points are (11,3) and (6,9)
assigning variables
(x1,y1) = (11,3) so x1 = 11 and y1 = 3
(x2,y2) = (6,9) so x2 = 6 and y2 = 9
plugging in values into formula
recall formula [tex]d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
==> plug in x1 = 11 , y1 = 3 , x2 = 6 and y2 = 9
[tex]d=\sqrt{(6-11)^2+(9-3)^2}[/tex]
==> subtract values in parenthesis
[tex]d=\sqrt{(-5)^2+(6)^2}[/tex]
==> evaluate exponents
[tex]d=\sqrt{25+36}[/tex]
==> add 25 and 36
[tex]d=\sqrt{61}=7.8[/tex] ( approximately )
