Answer :
The equation, in slope-intercept form, of the line that is perpendicular to the line y – 4 = –two-thirds(x – 6) is y = 3/2x - 1
Equation of a line in slope-intecept form?
The equation of a lins is a linear equation and expressed as:
y = mx + b
m is the slope
b is the y-intercept
Determine the equation in point slope form
y - y1 = -1/m(x - x1)
y -(-2) = 3/2(x + 2)
y + 2 = 3/2(x+2)
Write in slope-intercept form
2(y+2) = 3(x+2)
2y + 4 = 3x + 6
2y = 3x - 2
y = 3/2x - 1
Hence the equation, in slope-intercept form, of the line that is perpendicular to the line y – 4 = –two-thirds(x – 6) is y = 3/2x - 1
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