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Mathematics

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Segment (JG) bisect ∠FGH. Use the proportion from (FJ) to (FG) to find the missing length of (HJ)

Segment (JG) bisect ∠FGH. Use the proportion from (FJ) to (FG) to find the missing length of (HJ) class=

Answer :

Аноним Аноним

Today at 8:04 AM

GF/FJ=GH/HJ
6/4=9/HJ
3/2=9/HJ
3HJ=18
HJ=18/3
HJ=6

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Аноним Аноним

Today at 8:05 AM

Answer:

HJ = 6

Step-by-step explanation:

The sides are in the proportion :

[tex]\frac{FJ}{FG} = \frac{HJ}{HG}[/tex]

Therefore,

[tex]\frac{4}{6} = \frac{2}{3} = \frac{HJ}{9}[/tex]
HJ = 18/3
HJ = 6

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