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Answer:
given - circumference of the coin = 122 inches.
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[tex]\fbox\pink{Solution -}[/tex]
[tex]circumference = 2\pi \: r \\ \\ r = \frac{circumference}{2\pi} \\ \\r = \frac{\cancel{122}}{\cancel2 \times \frac{22}{7} } \\ \\ r = \frac{61}{ \frac{22}{7} } \\ \\ r = 61 \times \frac{7}{22} \\ \\ r = \frac{427}{22} \\ \\ r = 19.41 \: inches \: (approx.)[/tex]
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Answer :
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Step-by-step explanation :
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We know that,
[tex]{\longrightarrow \qquad \frak {\pmb{ 2 \pi r = Circumference_{(circle)} }}}[/tex]
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Here,
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Now, substituting the values :
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[tex]{\longrightarrow \qquad \sf{ 2 \times 3.14 \times r = 122}}[/tex]
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[tex]{\longrightarrow \qquad \sf{ 6.28 \times r = 122}}[/tex]
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[tex]{\longrightarrow \qquad \sf{ r = \dfrac{122}{6.28} }}[/tex]
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[tex]{\longrightarrow \qquad \frak{\pmb{ r = 19.42}}}[/tex]
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Therefore,
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